car accelerates uniformly with acceleration ‘a’ after starting from initial velocity ‘u’.
Derive the equation of motion by graphical method which is used to find the distance ‘s’
travelled by the car in‘t’ second
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Let the distance be “s”. We know that
Distance = Average velocity × Time. Also, Average velocity = (u+v)/2
Therefore, Distance (s) = (u+v)/2 × t
Also, from v = u + at, we have:
s = (u+u+at)/2 × t = (2u+at)/2 × t
s = (2ut+at²)/2 = 2ut/2 + at²/2
or s = ut +½ at²
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