car acceleration uniformly from 54 kmhour to 90 km/hour in 5 second calculate the acceleration and the distance travell by car
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Answer:
final velocity=90km/hr
initial velocity=54km/hr
accleration=change in velocity/time=(90-54)/5=26/5ms^-2
distance travelled can be calculated by using formula
v^2-u^2=2as
90^2-54^2=2x26/5xs where s is the distance travelled
8100-2916 =52/5s
52/5s=5184
s=5184 x 5/52
s=498.46
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