Question

car acquires a velocity of 72 km/h in 20 seconds starting from rest. FIND (a)the
acceleration( b )the distance travelled in this time

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Answer 1

$\mathfrak{\huge{\pink{\underline{\underline{AnswEr:-}}}}}$

Initial Velocity = u = 0

Final velocity = v = 72 km/hr = 72 x 5/18 = 20 m/s

Time = t = 10 sec

Acceleration = a

Equation of motion :-

v = u + at

20 = 0 + 10a

a = 20/10

a = 2 m/s²

displacement = distance traveled = s

Equation of motion :-

v² - u² = 2as

20² = 2 × 2 × s

400 = 4s

s = 400/4

s = 100 m

Average velocity = displacement / time

= 100 / 10

= 10 m/s

Answer 2

$\huge\bigstar\underline\mathfrak{Answer:-}$

Given:-

Initial Velocity , u= 0

Final velocity ,v = 72 km/hr = 72 x 5/18 = 20 m/s

Time, t = 10 sec

Acceleration ,a

________________

Equation of motion :-

v = u + at

20 = 0 + 10a

a = 20/10

a = 2 m/s²

displacement = distance traveled = s

_______________

Equation of motion :-

v² - u² = 2as

20² = 2 × 2 × s

400 = 4s

s = 400/4

s = 100 m

_____________________

Average velocity = displacement / time

= 100 / 10

= 10 m/s