Question

car covers two fifths of a 150-km road with a velocity of 60 km/h east and then continues to cover
the rest towards the east in another hour. Find its average speed and average velocity (in km/h).
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Answer 1

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Average speed and average velocity = 75km/h

$\orange{\mid{\underline{\overline{\textbf{explanation}}}\mid}}$

It is given that :-

Length of road = 150km

In first case distance traveled = 2/5 of road

With velocity = 60km/h

Second case travels left distance in time = 1hr

Average speed = ?

Average displacement = ?

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Now, in the first case distance traveled by car

$= \frac{2}{5} \times 150$

$= 60km$

Now the time taken to travel in first case =

$= \frac{60}{60} = \frac{d}{v}$

$= 1hr$

And it is given that the car then covers rest distance in 1 hr , so the total time taken in journey = 1hr + 1hr = 2hr.

And the total distance = 150 km, Now the average speed of car is :

$V_avg = \frac{150}{2} = 75km/ h$

And as there is no condition given in question that road is curved so we can say displacement = distance.

Thus average velocity = Average speed.

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BY SCIVIBHANSHU

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Answer 2

Answer:

A car covers two fifths of a 150-km road with a velocity of 60 km/h east and then continues to cover

the rest towards the east in another hour. Find its average speed and average velocity (in km/h).