Question

car having initial velocity 8m/s with a constant accerlation of 8m/s² on straight road the ratio of distance travelled by the car in first third and fifth second of motion
1:3:5
1:5:9
3:7:11
3:7:13​

Answer 1

Explanation:

Distance travelled in n

th

second =u+

2

a

(2n−1)

Distance travelled in 5

th

second =0+

2

8

(2×5−1)=36m