Question

car initially at rest starts moving with an acceleration of 6m/s2. The time in which it pick up a velocity of 48 m/s ​

Answer 1

Answer:

The time taken by car is 8 sec.

Explanation:

Given that, the car is initially at rest, this means that the initial velocity (u) will be 0m/s, the acceleration (a) is 6m/s² and the final velocity (v) of the car is 48m/s.

With this information, we are asked to find the time taken by the car.

We can find the time taken by the car using the first equation of motion.

$\begin{array}{l}\rm{\Rightarrow v = u + at} \\ \\ \rm{\Rightarrow 48 = 0 + 6 \times t} \\ \\ \rm{\Rightarrow 48 = 6 \times t} \\ \\ \rm{\Rightarrow t = \dfrac{48}{6}} \\ \\ \rm{\Rightarrow t = 8}\end{array}$

Hence, the time taken by the car is 8 sec.