Question

car is moving at a constant speed of 10 m/s. the time taken to cover a distance of 20 m is

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Answer 1

Answer:

2 seconds

Step-by-step explanation:

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Answer 2

Answer:

Case I. Suppose reduction time = t , so = 10 meters

then distance in t sec will be 10t meter

⇒ remaining distance = 10 meter - 10 t

using v

2

=u

2

−2as

we get s=

2a

u

2

−v

2

=

2a

(10)

2

−0

=

a

50

⇒

a

50

=10−10t _______ (1)

Case II

u=20 m/s & S

0

=30 meter

distance in t sec will be 20 t meter

distance during retardation S=

2a

u

2

−v

2

=

2a

(20)

2

−0

S=

a

200

S

0

=30m⇒

a

200

+20t=30

a

50

+5t=7.5 _______ (2)

using (1)

a

50

+10t=10