Question

car is moving at an average speed of 56 4/5 km/h. How much distance will it cover in 75 1/2. hours?
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Answer 1

$Average \;speed \:of \:car (s) = 56 \frac{4}{5} \\= \frac{284}{5} \: kmph$

$Time (t) = 75 \frac{1}{2} \\= \frac{151}{2} \: hours$

$\boxed { \pink { Distance \: covered (d) = \frac{s}{t} }}$

$d = \frac{ \frac{284}{5}}{\frac{151}{2}}\\= \frac{284}{5}\times \frac{2}{151} \\= 15\frac{15}{70} \: km$

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