Car is travelling with a speed of 36 km/h. The driver applied the brakes and retards the car uniformly. The car is stopped in 5 sec. Find (i) the acceleration of car and (ii) distance before it stops after appling breaks?
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Explanation:
v=u+at
v=0
u=36km/hr=10m/s
0= 10+5a
a=-2m/s^2
S=ut+1/2at^2
=50-25
S=25m
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