Car moving along a straight line at a speed of 54km/h stop in 5s after brakes are applied.
(A) find the acceleration?,assuming it to be constant.
(B) plot the graph of speed versus time
(C) using the graph,find the distance covered by the car after brakes are applied.
Answers
Answered by
377
Acceleration comes out to be -3.
and the graph and its use in taking out the distance covered.
explanation of part A.
given is:-
Initial velocity (u)=54 km/h that is 15 m/s.
Final velocity (v)=0
Time (t)=5 sec.
To find:-Acceleration (a)
solution:- v=u+at(first equation of motion)
substituting the values
0=15+a×5
0=15+5a
-15=5a
-15/5=a
-3=a
Therefore acceleration is -3.
OR
Retardation/deaccleration is 3.
Hope it will help.
Regards,
Anshuman Khare.
and the graph and its use in taking out the distance covered.
explanation of part A.
given is:-
Initial velocity (u)=54 km/h that is 15 m/s.
Final velocity (v)=0
Time (t)=5 sec.
To find:-Acceleration (a)
solution:- v=u+at(first equation of motion)
substituting the values
0=15+a×5
0=15+5a
-15=5a
-15/5=a
-3=a
Therefore acceleration is -3.
OR
Retardation/deaccleration is 3.
Hope it will help.
Regards,
Anshuman Khare.
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21
Answer:
37.5
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