car moving at 72 km per hour come to rest in 4 seconds find acceleration and distance
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72÷2=36 acceleration and distance coverd
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1
t=4sec...
u=72km/hr=72*5/18=20m/s
v=0m/s
a=(v-u)/t=0-20/4=-20/4= -5m/s².......
distance=ut+(1*at²)/2=20*4+(-5*16)/2=80-40=40m
u=72km/hr=72*5/18=20m/s
v=0m/s
a=(v-u)/t=0-20/4=-20/4= -5m/s².......
distance=ut+(1*at²)/2=20*4+(-5*16)/2=80-40=40m
Rushitha:
what about distance?... toplayer
watch it again.....
how u got -5
pls explain
........
tqsm...
final velocity is 0 bcz the car comes at rest and the initial velocity iz 20...........nd accelration=(final velocity-initial velocity)/time
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