Question

car moving at a speed of 10 m/s enters a highway and accelerates at 4 m/s2. How fast will the car be moving after it accelerated for 60m?

Answer 1

Answer:

v^2-u^2=2as

v^2= u^2+2as

v^2= 100+2×4×60

v^2=100+480

v^2=580

v~26m/s

Answer 2

Solution :

⏭ Given:

• Initial velocity = 10mps
• Acceleration = 4m/s$^2$
• Displacement of car = 60m

⏭ To Find:

• Final velocity of car

⏭ Formula:

✏ As per second equation of kinematics relation between initial velocity, final velocity, displacement and acceleration is given by...

$\bigstar \: \boxed{ \tt{ \red{ \large{ {v}^{2} - {u}^{2} = 2as}}}}$

⏭ Terms indication:

• u denotes initial velocity
• v denotes final velocity
• a denotes acceleration
• s denotes displacement

⏭ Calculation:

$\dashrightarrow \sf \: {v}^{2} - {(10)}^{2} = 2 \times 4 \times 60 \\ \\ \dashrightarrow \sf \: {v}^{2} = 480 + 100 \\ \\ \dashrightarrow \sf \: {v}^{2} = 580 \\ \\ \dashrightarrow \: \boxed{ \tt{ \pink{v = 24.08 \: mps}}}$

⏭ Additional information:

• Velocity is a vector quantiy.
• Vector quantity has both magnitude as well as direction.