Question

Car moving with a velocity of 10 metre per second can be stopped by the application of a constant force f in a distance of 20 m if the velocity of the car is 30 metre per second it can be stopped by this force in

Answer 1

Answer:

180 meters

Explaination:

We'll use the equation of motion:

v^2 - u^2 = 2×a×s

Here, v = 0 m/s as the car stops in the end.

Also, since a deceleration is happening, we'll write 'a' as '-a'

So, the equation modifies to become as follows:

- u^2 = 2×(-a)×s

u^2 = 2×a×s

s = (u^2)/(2×a)

1. 20 = 10^2/(2×a) => 2×a = 5
2. s = 30^2/(2×a) => s = 900/5 => [s = 180 meters]