Question

Car moving with constant acceleration covers the distance between two points 180m apart in 6sec. its speed as it passes the second part is 45m/s. what is the acceleration and speed at first point

Answer 1

s=180m
t=6s
v=45m/s
u=?
a=?

speed. =distance/time
= 180/6
Average Velocity =30m/s

average Velocity=v+u/2
30 =45+u/2
30x2=45+u
60=45+u
therefore,u=60-45
=15m/s


v=u+at
45=15+a(6)
30=6a
therefore,
a=5m/s sq.