Question

car of 700 kg moving with 90 km/h is brought to rest calculate work done by brake​

Answer 1

Answer:

The work done to stop the car is 2,18,750 J.

Explanation:

The work done to stop the car will be equal to the kinetic energy of the car. A force should be applied in a direction opposite to the motion of the car. The kinetic energy of the car can be found using the following equation:

K.E = 1/2 (mv²)

Where 'm' is the mass and 'v' is the velocity of the body.

We have, the mass of the car, m = 700 Kg

The velocity of the car, v = 90 Km/h = 25 m/s

∴ The kinetic energy of the car, K.E = 1/2 (700 × 25²)

                                                           = 1/2 (700 × 625)

                                                           = 2,18,750 J

∴ The work done to stop the car is 2,18,750 J.