car of a mass 1500kg travelling at 25m/s colloids with another car B of a mass 1000kg travelling 15m/s in the same fire. after the collision the velocity of car A become 20m/s. calculate the velocity of car B after the collision
Answers
Answer:Thus, velocity of car 'B' after collision is 22.5m/s.
Explanation:
Answer:
Let,
Let,mass = m
Let,mass = minitial velocity = u
Let,mass = minitial velocity = ufinal velocity = v
Let,mass = minitial velocity = ufinal velocity = vhere,
m₁= 1500 kg m₂=1000 kg
u₁ = 25 m/s
U₂ = 15 m/s
V₁ = 20 m/s
we have to find v₂ !!
V2 is the velocity after collision
Here is a formula relating the values given,
m₁u₁+m₂u₂ = m₁v₁ + m₂+V₂
mquq+m2U2 = = 1500 × 25 +1000 x15
= 37500 + 15000
= 52500
m₁u₁+m₂u₂ = m₁v₁ + m₂+V₂
m_{1}*u_{1} + m_{2}*u_{2} = 1500 * 25 + 1000 * 1!
= 37500 + 15000
= 52500
m_{1}*v_{1} + m_{2} + v_{2} = 1500 * 20 + 1000v_{2}
= 30000 + 1000v₂
m₁U₁+M₂U₂ = m₁v₁ + m₂+V2
52500 = 3000 + 1000v_{2}
1000v_{2} = 52500 - 30000
1000v_{2} = 22500 v_{2} = 22500/1000
= 22.5 m/s
Thus, velocity of car 'B' after collision is 22.5m/s.
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