Question

car of mass 1000 kg is brought to rest from a speed of 40 m - in a distance of 80 m. find the braking force of the car assuming that it is constant and that there is a constant resistance to motion of 100 newton​

Answer 1

Answer:

Explanation

car of mass 1000 kg is brought to rest from a speed of 40 m - in a distance of 80 m. find the braking force of the car assuming that it is constant and that there is a constant resistance to motion of 100 newton​:$\left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right.$

Answer 2

Answer: -10000

Explanation:

Initial velocity = 40

Final velocity = 0

X= u^2/2a

80=1600/2a. therefore a= 10

F= ma 1000×10= -10000

-ve sign because it's a retarding force ;)