car of mass 1000 kg travelling with the velocity of 14 metre per second stops in 28 seconds calculate it's initial momentum and final momentum, change in momentum and force applied by the brakes
Answers
Answer:
Initial momentum = 28000 kg m/s
Final momentum = 0
Change in momentum = -28000 kgm/s
force applied by brakes = -500 N
Step by step Explanations :
Given that,
A car of mass 1000 kg travelling with the velocity of 14 m/s
and ,
brakes are applied to stop it
and it stopped in 28 seconds
so,
now we have ,
initial velocity of the car(u) = 14 m/s
final velocity of car(v) = 0 m/s
time(t) = 28 s
so,
acceleration(a) = (v - u)/t
= (0 - 14)/28
= -14/28
= -1/2
= -0.5 m/s²
Negation of acceleration shows the retardation
now,
Initial momentum
= mass × initial velocity
putting the values
1000 × 28
= 28000 kg m/s
Final momentum
= mass × final velocity
= 1000 × 0
= 0
now ,
Change in momentum
= final momentum - initial momentum
= 0 - 28000
= -28000 kg m/s
force applied by brakes
= mass × acceleration
= 1000 × (-0.5)
= -500 N
so,
Initial momentum = 28000 kg m/s
Final momentum = 0
Change in momentum = -28000 kgm/s
force applied by brakes = -500 N
Given,
mass = 1000 kg
u = 14 m/s
v = 0
time = 28 s
so,
acceleration
= (0 - 14)/28
= -14/28
= -0.5 m/s²
now,
Initial momentum
= mu
1000 × 28
= 28000 kgm/s
Final momentum
= mv
= 1000 × 0
= 0
force applied by brakes
= ma
= 1000 × (-0.5)
= -500 N
so,
Initial momentum = 28000 kg m/s
Final momentum = 0
Change in momentum = -28000 kgm/s
force applied by brakes = -500 N