Physics, asked by sapnarenuprasapbe91l, 11 months ago

car of mass 1000 kg travelling with the velocity of 14 metre per second stops in 28 seconds calculate it's initial momentum and final momentum, change in momentum and force applied by the brakes​

Answers

Answered by deepsen640
90

Answer:

Initial momentum = 28000 kg m/s

Final momentum = 0

Change in momentum = -28000 kgm/s

force applied by brakes = -500 N

Step by step Explanations :

Given that,

A car of mass 1000 kg travelling with the velocity of 14 m/s

and ,

brakes are applied to stop it

and it stopped in 28 seconds

so,

now we have ,

initial velocity of the car(u) = 14 m/s

final velocity of car(v) = 0 m/s

time(t) = 28 s

so,

acceleration(a) = (v - u)/t

= (0 - 14)/28

= -14/28

= -1/2

= -0.5 m/s²

Negation of acceleration shows the retardation

now,

Initial momentum

= mass × initial velocity

putting the values

1000 × 28

= 28000 kg m/s

Final momentum

= mass × final velocity

= 1000 × 0

= 0

now ,

Change in momentum

= final momentum - initial momentum

= 0 - 28000

= -28000 kg m/s

force applied by brakes

= mass × acceleration

= 1000 × (-0.5)

= -500 N

so,

Initial momentum = 28000 kg m/s

Final momentum = 0

Change in momentum = -28000 kgm/s

force applied by brakes = -500 N

Answered by ILLIgalAttitude
58

Given,

mass = 1000 kg

u = 14 m/s

v = 0

time = 28 s

so,

acceleration

= (0 - 14)/28

= -14/28

= -0.5 m/s²

now,

Initial momentum

= mu

1000 × 28

= 28000 kgm/s

Final momentum

= mv

= 1000 × 0

= 0

force applied by brakes

= ma

= 1000 × (-0.5)

= -500 N

so,

Initial momentum = 28000 kg m/s

Final momentum = 0

Change in momentum = -28000 kgm/s

force applied by brakes = -500 N

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