Question

car of mass 1800 Kg, moving with a speed

of 10m/s is brought to rest after
Covering a distance of 80m calculate thee
force action on the car?


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Answer 1

Given :-

• A car of mass 1800 kg, moving with a speed of 10m/s is brought to rest after covering a distance of 80m

To find :-

• The force action on the car.

Solution :-

• Mass of car (m) = 1800kg

• Initial velocity (u) = 10m/s

• Final velocity (v) = 0

• Distance covered (s) = 80m

According to third equation of motion

• → v² = u² + 2as

• → (0)² = (10)² + 2 × a × 80

• → 0 = 100 + 160a

• → 160a = - 100

• → a = - 100/160

• → a = - 0.625m/s²

Hence, acceleration of car is - 0.625m/s²

As we know that

• → Force = mass × acceleration

• → F = m × a

• → F = 1800 × (-0.625)

• → F = - 1125 N

• Force will be acting in the opposite direction

Therefore,

• The force action on the car is - 1125 N