Question

car of mass 2500kg accelerates at the rate of 4m/s2 and then at the rate of 16 m/s2.

Calculate the ratio of the forces exerted by the engine in the two cases?

Answer 1

f=ma
f1=2500*4=10000
f2=2500*16=40000
ratio =10000/40000
=1ratio 4

Answer 2

Answer:

F= m×a

F1 2500×4=10000

F2 2500×16=40000

ratio 10000/40000

1:4 ans