Question

Car parking design major problem in urban areas in both developed and developing countries

in the Jaipur city GT mall, a shopping place charge the parking. The charges of a car in parking

lot is Rs. 30 for the first two hour and Rs. 10 for subsequent hour, then answer the following

question

(I) Taking total working time to be x hour and total charges as Rs. Y, then linear equation is

(1mark)

(a) + − = . (c) − + =

(b) + − = . (d) − + =

(II) If y=20 the value of x is. (1mark)

(a) 2. (b) 1. (c) 4. (d) 3

(III) If x=3 the value of y is. (1mark)

(a) 10. (b) 20. (c) 30. (d)40

(IV) If charges of a car in parking lot is Rs 50 for first two hours , then the linear equation is

(1mark)

(a) − + = . (c) + − =

(b) + + = . (d) + − =

(V) If charges for subsequent hour is Rs. 8 , then the linear equation is

(a) − + = . (c) − + = . (1mark​

Answer 1

Step-by-step explanation:

Parking charges for first 2 hrs=Rs 30 Parking charges for subsequent hrs = Rs 1 Total park time = x hours Total arges = Rsy : y = 30 + 10(x - 2); y = 30 + 10x - 20; 10x - y = - 10 X 1 20 2 30 3 40 y

From the graph, it is clear that for five hours, parking charges will be Rs 60.