Question

Car parking is a major problem in urban areas in both developed and developing Countries. In the Jaipur City , a shopping mall, charged the parking. The charges of car in parking lot is ₹ 50 for the first two hours and ₹ 10 for the subsequent hours, then what will be the linear equation​

Answer 1

$\huge\tt\fcolorbox{cyan}{Lime}{ ANSWER♡࿐}$

$\bigstar \: \boxed{\sf{\color{purple}{Given:}}}$

parking charges for the first two hours = ₹30

and for subsequent hours = ₹ 10

Total parking time = xh and total charges = ₹y

$\bigstar \: \boxed{\sf{\color{purple}{Then,}}}$

according to the given condition,

30 + 10(x-2) = y=> 30 + 10x -20 = y

=>10x + 10-y = 0

=>10x-y+10 = 0 (i)

which is the required linear equation in two variables.

It can also be written as

y = 10x + 10 (i)

Now, for drawing the graph, we need atleast two solutions of the equation.

When x = 0, then y = 10(0) +10 = 10

When x = -1, then y = -10 + 10 = 0

When x = 1, then y = 10(1) + 10 = 20

So, we have the following table to draw the graph.

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$\sf\red{Thank\:you!}$