car started from Town P and travelled towards Town Q at 70 km/h. At the same time a van started from Town Q and travelled to Town P at 60 km/h. After 23 hours, they were 65 km apart, still travelling 2 towards each other. (1) What is the distance between the two towns? (ii) After how many hours of travel would they cross each other?
Answers
Step-by-step explanation:
yourself this answer I hope it help
Answer:
Distancebetweentwotowns=422.5km
\bold{\underline{\underline{Step-by-step\:explantion:}}}
Step−by−stepexplantion:
• In the given question information given about two cars start from town P and town Q in opposite direction at the speed of 70 km/h and 60 km/h. After 11/4 hours the distance between those two cars is 65 km apart.
• We have to find the distance between two towns.
\begin{gathered} \underline \bold{Given : } \\ \implies Speed \: of \: car \: P = 70 \: kmh \\ \\ \implies Speed \: of \: car \: W = 60\: kmh \\ \\ \underline \bold{To \: Find: } \\ \implies Distance \: between \: town \: P \: and \: Q = ?\end{gathered}
Given:
⟹SpeedofcarP=70kmh
⟹SpeedofcarW=60kmh
ToFind:
⟹DistancebetweentownPandQ=?
• According to given question :
\begin{gathered} \bold{For \: car \: P : } \\ \implies Distance = speed \times time \\ \\ \implies D = \cancel{70} \times \frac{11}{ \cancel4} \\ \\ \implies D = \frac{ \cancel{385}}{ \cancel2} \\ \\ \bold{\implies D = 192.5 \:km} \\ \\ \bold{For \: car \: Q : } \\ \implies Distance = speed \times time \\ \\ \implies D_{2} = \cancel{60} \times \frac{11}{ \cancel4} \\ \\ \implies D_{2} = 15 \times 11 \\ \\ \bold{\implies D_{2} = 165 \: km} \\ \\ \bold{ Total \: distance \: between \: town \: P \: and \: Q :} \\ \implies Distance \: covered \: by \:car \: P+ car \: Q+ 65 \: km \\ \\ \implies Total \: Distance = d + d_{2} + 65 \\ \\ \implies Tota l \: Distance = 192.5 + 165 + 65 \\ \\ \bold{\implies Tota l \: Distance =422.5 \:km} \\ \\ \bold{\therefore Distance \:between \: town \: p \: and \: q }\\ \bold{ \: \: \: \: is \: 422.5 \: km}\end{gathered}
ForcarP:
⟹Distance=speed×time
⟹D=
70
×
4
11
⟹D=
2
385
⟹D=192.5km
ForcarQ:
⟹Distance=speed×time
⟹D
2
=
60
×
4
11
⟹D
2
=15×11
⟹D
2
=165km
TotaldistancebetweentownPandQ:
⟹DistancecoveredbycarP+carQ+65km
⟹TotalDistance=d+d
2
+65
⟹TotalDistance=192.5+165+65
⟹TotalDistance=422.5km
∴Distancebetweentownpandq
is422.5km