Question

Car starting from rest moving with uniform acceleration attains a speed of 36km/h in 10sec.Find it's acceleration​

Answer 1

Answer:

$Acceleration (a)=1 \ m/sec^2$

Explanation:

Given :

Initial velocity ( u ) = 0 m / sec

Final velocity ( v )  = 36 km / hr

To convert km / hr into m / sec multiply by 5 / 18 we get

u = 2 × 5 = 10 m / sec

Time ( t ) = 10 sec

From first equation of motion we have

v = u + a t

where

v = Final velocity

u = Initial velocity

a = Acceleration

t = time

Now put these value in equation

10 = 0 + a × 10

10 = 10 a

a = 10 / 10

a  =  1 $m/sec^2$

Thus we get answer.

Answer 2

» Car starting from rest moving with uniform acceleration attains a speed of 36km/h in 10 sec.

Here ..

• Initial velocity (u) = 0 m/s (beacuse car is staring from rest.)

• Final velocity (v) = 36 km/hr

=> 36 × $\dfrac{5}{18}$

=> 2 × 5

=> 10 m/s

• Time (t) = 10 sec

______________ [ GIVEN ]

• We have find it's acceleration.

____________________________

We know that ..

v = u + at

(From First Equation Of Motion)

Put the known values in above formula.

→ 10 = 0 + a(10)

→ 10a = 10

→ a = 10/10

→ a = 1

We have unit of velocity = m/s and of time is sec

Acceleration = Velocity/time

=> (m/s) ÷ sec

So, unit of acceleration = m/s²

→ a = 1 m/s²

______________________________

1 m/s² is the acceleration.

___________ [ ANSWER ]

_______________________________