car starts from rest, accelerates uniformly and attains a velocity of 20 m/s with in 50 metres. Find acceleration. *
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Using Third equation of motion,
2as=v^2-u^2
2*50*a=(20^2)-(0^2)
100a=400
a=400/100=4m/s^2
HERE a= Acceleration
s=distance
v=final velocity
And u=intial velocity
2as=v^2-u^2
2*50*a=(20^2)-(0^2)
100a=400
a=400/100=4m/s^2
HERE a= Acceleration
s=distance
v=final velocity
And u=intial velocity
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