car starts from rest acquires velocity 15 M per second in 120 seconds find acceleration and distance travelled during this time
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Hi Mate Here is Your Answer,
GIVEN :
V= 15m/sec
T= 120 sec.
U=0 m/sec
A=?
How to find acceleration?????
We can simply find it by applying the below written Formula.....
a = (v-u)/t
Now in this formula substitute the given values than solve the equation ;
a= (15-0)/120
a= 15/120 = 5/40 = 1/8 = 0.125......... (Ans.)
● ANS IS 0.125 M/SEC^2
From second law of motion we know
S= Ut+1/2 × a×t^2
Now substitute Values,
S= 0×120+1/2× 1/8 x 120 ×120
S= 1/2×1/8×120×120
S= 1/16×120×120
S= 900
● So the distance is 900m.
HOPE THIS HELPS YOU A LOT......☺♤♤♤♤
GIVEN :
V= 15m/sec
T= 120 sec.
U=0 m/sec
A=?
How to find acceleration?????
We can simply find it by applying the below written Formula.....
a = (v-u)/t
Now in this formula substitute the given values than solve the equation ;
a= (15-0)/120
a= 15/120 = 5/40 = 1/8 = 0.125......... (Ans.)
● ANS IS 0.125 M/SEC^2
From second law of motion we know
S= Ut+1/2 × a×t^2
Now substitute Values,
S= 0×120+1/2× 1/8 x 120 ×120
S= 1/2×1/8×120×120
S= 1/16×120×120
S= 900
● So the distance is 900m.
HOPE THIS HELPS YOU A LOT......☺♤♤♤♤
harmanwarring8p83l9m:
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