car starts from rest and attains velocity of 20 m/s in 20 sec. The distance travelled in the car during this period is: *
100 m
200 m
300 m
400 m
Answers
Answered by
4
Explanation:
to 20 m/s in 5 seconds.
The distance d is from
d = v(avg) • t
where v(avg) is the average velocity during the time, or
v(avg) = v(initial) + ∆v/2.
Here v(initial) is 0 and ∆v is 20 m/s, so
v(avg) = 20 m/s / 2 = 10 m/s.
d = 10 m/s • 5 s = 50 m.
Answered by
3
Given:
The initial velocity of the car, u = 0
The final velocity of the car, v = 20 m/s
The total time taken by the car, t = 20 sec
To Find:
The distance travelled by the car during this period.
Calculation:
- Using the first equation of motion, we have:
v = u + at
⇒ 20 = 0 + a × 20
⇒ a = 20 / 20
⇒ a = 1 m/s²
- Now using second equation of motion, we get:
s = ut + 1/2 at²
⇒ s = 0 × 20 + 1/2 × 1 × (20)²
⇒ s = 400/2
⇒ s = 200 m
- So, the distance travelled by the car during this period is 200 m.
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