Question

car starts from rest and moves along the x axis with constant acceleration 5 metre per second square for 8 seconds if it then continues with constant velocity what distance will the car cover in 12 seconds since it started from the rest ​

Answer 1

Answer:

The distance travelled in first 8 s, x1= 0 + 1 /2 (5) (8) 2 = 160 m. At this point the velocity v = u+ at = 0 + (5×8) =40 m s–1 Therefore, the distance covered in last four seconds, x2 = (40 × 4) m =160 m Thus, the total distance x = x1+x2 = (160+ 160) m = 320 mRead more on Sarthaks.com - https://www.sarthaks.com/10350/car-starts-from-rest-and-moves-along-the-x-axis-with-constant-acceleration-5-m-s-for-seconds