car starts from rest and moves with constant acceleration of 5 metre per second square for 8 seconds if it continues with constant velocity what distance will the car covers in 12 second starting from rest
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A car starts from rest and moves along the x-axis with constant acceleration 5ms-2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest ? v=u+at=0+5×8=40m/s.
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Initial velocity, u = 0 m/s ( Since the car is at rest )
Final velocity, v = ?
acceleration, a = 5 m/s²
Time, t = 12 s
We know,
h = ut + 1/2 at²
Substituting the values
distance travelled = 0×12 + 5×144 / 2
distance travelled = 5 × 72
distance travelled = 360 m
Hence, the car will cover 360 m .
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