Question

car travel 8km from garage. find component of car displacement

Answer 1

Answer:

A car moves 8 km south and then 6 km east. What is the total distance and displacement travelled by the car?

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South and East imply that you are on a global coordinate system. In other words, you would be on the surface of a sphere.

So, for absolute precision, the 2-dimensional Pythagorean theorem does not apply. We live in a 3-dimentional world.

For example, if the trip started on the North pole, after moving 8 km to the south (the only direction you could move, along a longitude), the subsequent Eastward movement (along a latitude near but not quite 90 degrees north) would follow an 8 km radius arc around the North pole starting point, and thus you’d never change from being 8 km from the North pole.

Eve

A person travels 6 km west. He then turns left and travels 8 km. What is the displacement?

A boy walks 7 km west, then 4 km north, and finally 4 km east. What is his final displacement?

A car travels 4 km East and then 9 km North. What is the distance traveled by the car?

A car travels 15 km south 30° east and 8 km due west. What will be the resultant displacement?

A body moves 6 km west and 8 km north. What is the distance and displacement?

The car’s distance traveled is 8 + 6 = 14 km, the total amount of movement.

The car’s displacement has two components, a number of km and the direction of the final position from the initial position.

The car’s displacement is the hypotenuse of the triangle, 10 km southeast of the initial position.

But southeast is only a rough estimate of the direction.

The tangent of the angle is 6/8 or .75, so the amount of angle to the east of south is 37 degrees.

South (180 degrees) minus 37 degrees is 143 degrees.

The car’s displacement is more accurately called 10 km in a direction of 143 degrees from the initial point

Answer 2

Driving 8km from the garage and part of the car evacuation is:

• The car must first be in A and the AC must face south.
• Then, b = 8km and a = 6km.
• C will provide vehicle displacement as removal is the shortest distance between the first and last point.
• C 2 = a 2 + b 2. c = 8 2 + 6 2 = 64 + 36 = 100 = 10 k m.
• Therefore, the traffic is 10km.

• The car removal has two parts, the mile number and the direction of the final location from the starting point.
• The vehicle removal is a triangular hypotenuse, 10 km southeast of the original location.
• But the Southeast is the only bad measure of guidance.