Question

car travelling at a speed of 30 km per hour is brought to halt in 8 metre by applying brakes if the speed of the car is 60 kilometre per hour calculate distance at which it will be brought to halt by same breaking power​

Answer 1

Answer:

Answer:

32m

Explanation:

v² = u² + 2as…….. where a: retardation (opposite of acceleration) and s: distance covered.

1st case:

u = 30 km/h = 25/3 m/s

v = 0,

s = 8 m

Therefore, 0² = (25/3)² - 2 × a × 8

This gives a = 4.34 m/s²

2nd case:

u = 60 km/h = 50/3 m/s

v = 0

a = 4.34 m/s²

Now, 0² = (50/3)² - 2 × 4.34 × s

This gives s = 32 m

Thus on applying brakes the car will stop after covering 32 m.