car travels at speed X m/s from A to B, and returns From B to A at speed of Y m/s , find average speed of car
2 points
Answers
Answered by
66
Answer:
- Average speed of the car is 2XY/(Y + X) m/s.
Step-by-step explanation:
Given that:
- A car travels at speed X m/s from A to B.
- And returns from B to A at speed of Y m/s.
To Find:
- Average speed of the car.
Let us assume:
- The distance from A to B be Z.
We know that:
- Distance = Speed × Time
- Time = Distance/Speed
- Speed = Distance/Time
- Average speed = Total distance/Total time
Finding the time to cover distance from A to B:
- Time = Distance/Speed
- Time = Z/X
Finding the time to cover distance from B to A:
- Time = Distance/Speed
- Time = Z/Y
Finding the total time taken:
- A to B = Z/X
- B to A = Z/Y
- Total time = Z/X + Z/Y
- Total time = Z(1/X + 1/Y)
- Total time = Z(Y + X)/XY
Finding the total distance:
- A to B = Z
- B to A = Z
- Total distance = 2Z
Finding the average speed of car:
- Average speed = Total distance/Total time
We have.
- Total distance = 2Z
- Total time = Z{Y + X)/XY
- Average speed = 2Z/{Z(Y + Z)/XY}
- Average speed = (2Z × XY)/{Z(Y + X)}
- Average speed = 2XY/(Y + X)
Hence,
- Average speed of the car = 2XY/(Y + X) m/s
Answered by
18
Given :-
Car travels at speed X m/s from A to B, and returns From B to A at speed of Y m/s ,
To Find :-
Average speed
Solution :-
Let the distance be d
We know that
Time = Distance/Speed
Time = d/x
When B to A
Time = d/y
Now,
The total time taken by A and B
d/x + d/y
Taking d as common
d(1/x + 1/y)
d(1 + 1/xy)
d(y + x/xy)
Now
The total distance covered by A and B
Total Distance = d + d
Total Distance = 2d
Avg. Speed = 2d/d(x + y)/xy
Avg. speed = 2d(xy)/d(y + x)
Avg. Speed = 2xy/y + x
Similar questions