Math, asked by Pathanjuned60, 2 months ago

car travels at speed X m/s from A to B, and returns From B to A at speed of Y m/s , find average speed of car
2 points

Answers

Answered by TheBrainliestUser
66

Answer:

  • Average speed of the car is 2XY/(Y + X) m/s.

Step-by-step explanation:

Given that:

  • A car travels at speed X m/s from A to B.
  • And returns from B to A at speed of Y m/s.

To Find:

  • Average speed of the car.

Let us assume:

  • The distance from A to B be Z.

We know that:

  • Distance = Speed × Time
  • Time = Distance/Speed
  • Speed = Distance/Time
  • Average speed = Total distance/Total time

Finding the time to cover distance from A to B:

  • Time = Distance/Speed
  • Time = Z/X

Finding the time to cover distance from B to A:

  • Time = Distance/Speed
  • Time = Z/Y

Finding the total time taken:

  • A to B = Z/X
  • B to A = Z/Y

  • Total time = Z/X + Z/Y
  • Total time = Z(1/X + 1/Y)
  • Total time = Z(Y + X)/XY

Finding the total distance:

  • A to B = Z
  • B to A = Z

  • Total distance = 2Z

Finding the average speed of car:

  • Average speed = Total distance/Total time

We have.

  • Total distance = 2Z
  • Total time = Z{Y + X)/XY

  • Average speed = 2Z/{Z(Y + Z)/XY}
  • Average speed = (2Z × XY)/{Z(Y + X)}
  • Average speed = 2XY/(Y + X)

Hence,

  • Average speed of the car = 2XY/(Y + X) m/s
Answered by Anonymous
18

Given :-

Car  travels at speed X m/s from A to B, and returns From B to A at speed of Y m/s ,

To Find :-

Average speed

Solution :-

Let the distance be d

We know that

Time = Distance/Speed

Time = d/x

When B to A

Time = d/y

Now,

The total time taken by A and B

d/x + d/y

Taking d as common

d(1/x + 1/y)

d(1 + 1/xy)

d(y + x/xy)

Now

The total distance covered by A and B

Total Distance = d + d

Total Distance = 2d

Avg. Speed = 2d/d(x + y)/xy

Avg. speed = 2d(xy)/d(y + x)

Avg. Speed = 2xy/y + x\\

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