car travels from stop A to stop B with a speed of 30 km/h and then returns back to A
with a speed of 50 km/h. Find
3M
(i) displacement of the car.
(ii) distance travelled by the car.
(iii) average speed of the car.
Answers
Answered by
0
Answer:
(i) 20km
(ii) 70km
(iii) 35km/h
Explanation:
Answered by
0
Explanation:
u =30
v=50
t =3 min. =180 sec.
Distance =(30+50) * 180
=32400 m = 32.4 Km
Displacement same as distance.
Avg. Speed = distance /time
= 30+50/180
= 1 km/hr
Similar questions