car travels from stop A to stop B with। a speed of 30km/h and then returns nack to A with a speed of 50km/h. Find: (a) Displacement of car. (b) Distance travelled by the car. (c) Average speed of the car
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Displacement=30km/h
Average speed=50+30/2=80/2=40km/h
Distance=v*t=40*1=40km
Average speed=50+30/2=80/2=40km/h
Distance=v*t=40*1=40km
alismanggalisp8v52b:
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(a) Displacement will be 0 as it returns to the same position.
(b) Need more data to find out distance.
(c) Average Speed = 2ab/a+b
So, Average speed = 2×50×30/50+30 = 37.4km/hr
(b) Need more data to find out distance.
(c) Average Speed = 2ab/a+b
So, Average speed = 2×50×30/50+30 = 37.4km/hr
Average speed =30km/hr+50km/hr/2hr=40km/hr
Distance =80km
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