Question

car travels with a velocity of 2 metre per second and come to rest after 10 seconds calculate its acceleration.​

Answer 1

Explanation:

given

u=2m/s

v=0m/s (comes to rest)

t=10sec

a=v-u÷t

a= 0-2÷10

=-2÷10=-5 retardation

Answer 2

Answer:

• $\sf{-0.2 \:m/s^2}$

Explanation:

$\star\:{\underline{\underline{\tt{\red{GIVEN}}}}}:-$

• $\textsf{Initial velocity (u) = 2m/s}$
• $\textsf{Final velocity (v) = 0m/s}$
• $\textsf{Time taken (t) = 10 s}$

$\star\:{\underline{\underline{\tt{\orange{TO\: FIND }}}}}:-$

• $\textsf{Acceleration (a)}$

$\star\:{\underline{\underline{\tt{\green{SOLUTION}}}}}:-$

$\underline{\boxed{\sf{\blue{a = \dfrac{v-u}{t}}}}}$

$\textsf{Where,}$

• $\textsf{v is the final velocity}$
• $\textsf{a is the acceleration }$
• $\textsf{u is the initial velocity}$
• $\textsf{t is the time taken}$

$\dag\:\underline{\mathfrak{\purple{Substituting\: the\: values }}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf\orange{ a = \dfrac{0-2}{10}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf\blue{ a = \dfrac{-2}{10}}$

$\tiny\qquad\quad\rightarrow\:\:\:\:\sf\red{ a = -0.2m/s^2}$

$\dag\:\underline{\mathfrak{\purple{Hence,}}}$

• $\sf{Acceleration\: of \:the \:car \:is\: -0.2 m/s^{2}}$