car travels with constant velocity 40km/h and another half with a constant velocity of 60km/h along a straight line. the average velocity of the car is
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Suppose total length of the straight line (d) = (x) km.
Now, The first half (x/2 km) is travelled with 40km/h and aother half (x/2 km) is travelled with 60km/h velocity.
So, for the first half time (t1) = distance/velocity.
t1 = (x/2)/40 hours.
And, for the second half time (t2) = distance/velocity.
t2 = (x/2)/60 hours.
So total time taken (T) = t1 + t2
(T) = (x/2)/40 + (x/2)60 hours.
(T) = x/80 + x/120 hours.
(T) = (3x + 2x)/240 = 5x/240 hours.
(T) = x/48 hours.
Now, Average Velocity (v) = d/T
v = x/(x/48)
v = 48x/x
v = 48 km/h.....●..ans.
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Now, The first half (x/2 km) is travelled with 40km/h and aother half (x/2 km) is travelled with 60km/h velocity.
So, for the first half time (t1) = distance/velocity.
t1 = (x/2)/40 hours.
And, for the second half time (t2) = distance/velocity.
t2 = (x/2)/60 hours.
So total time taken (T) = t1 + t2
(T) = (x/2)/40 + (x/2)60 hours.
(T) = x/80 + x/120 hours.
(T) = (3x + 2x)/240 = 5x/240 hours.
(T) = x/48 hours.
Now, Average Velocity (v) = d/T
v = x/(x/48)
v = 48x/x
v = 48 km/h.....●..ans.
Please mark as brainliest if it was helpful.
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