car under accelerated motion covers 20 m in first first 2 seconds what will be the distance travelled in 3 seconds if car starts from rest
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heya!
Given:
Initial velocity = u =0m/s
Distance travelled =S=20m
time =t=2sec.
From second equation of motion:
S=ut + 1/2 at²
20= 0*2+ 1/2a2²
20=2a
a=10m/s²
velocity at the end of 2sec:
V=u+at
=0+10*2
V=20m/s
After 3sec, it covers a distance of 160m
so,
d=20*3+1/2*10*3^2
d= 60+45
so it is 125 m/s
hope it helps u n plse mark as brainlist
Given:
Initial velocity = u =0m/s
Distance travelled =S=20m
time =t=2sec.
From second equation of motion:
S=ut + 1/2 at²
20= 0*2+ 1/2a2²
20=2a
a=10m/s²
velocity at the end of 2sec:
V=u+at
=0+10*2
V=20m/s
After 3sec, it covers a distance of 160m
so,
d=20*3+1/2*10*3^2
d= 60+45
so it is 125 m/s
hope it helps u n plse mark as brainlist
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