Question

Carbon-12 to carbon-14 ratio in an animal fossil is found to be one fourth of the ratio in the bone of living animal. The half life of carbon-14 is 5730 years, how old is the fossil? ​

Answer 1

Explanation:

14

C

=

16

1

=

N

0

N

∵

N

0

N

=(

2

1

)

n

⇒

16

1

=(

2

1

)

n

⇒(

2

1

)

4

=(

2

1

)

n

⇒n=4

⇒(

T

1

)=4

t=4×T=4×5730=22920 years