Carbon-14 has a half-life of 5730 years. How much of a 144 g sample of carbon-14 will remain after 1719 years?
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Answered by
0
The half life of carbon- 14 is t 12=5730y. This means that in 5730y , the initial amount of carbon −14 will be halved ... m=144⋅e−0.000121⋅1719=144⋅e−0.208= 117g ...
Answered by
1
Explanation:
11,554.53 years old is a mammoth's tusk.
Explanation:
\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{5730 year}= 0.000120 year^{-1}λ=
t
2
1
0.693
=
5730year
0.693
=0.000120year
−1
N=N_o\times e^{-\lambda t}N=N
o
×e
−λt
N = amount left after time t = 25\%25% of a = 0.25 a
N_oN
o
= initial amount = a
\lambdaλ = rate constant
t= time = ?
\log[N]=\log[N_o]-\frac{\lambda t}{2.303}log[N]=log[N
o
]−
2.303
λt
\log\frac{N}{N_o}=-\frac{\lambda\times t}{2.303}log
N
o
N
=−
2.303
λ×t
t = 11,554.53 years
11,554.53 years old is a mammoth's tusk.
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