carbon and hydrogen combine to form 3 compounds a ,b and c the % of the compounds are 25 14.3 7.7respectively .'show that data illustrate the law of multiple proportions.
Answers
The law of multiple proportions
This law states that when two elements combine with each other to form more than one compound, the weights of one the element that combine with a fixed weight of the other element are in a ratio of small whole numbers.
We can calculate the ratio of the C:H in each of the compounds formed:
C = 25% , H = 75% Ratio is 1:3
C = 14.3% , then H = 85.7 Ratio is 1: 5.99 = 1:6
C = 7.7% , H = 92.3% 1:11.98701 = 1:12
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Proving the Law of Multiple proportions:
We will take the ratios of the hydrogen(3,6 and 12) and divide by the smallest number of the ratios, which is 3.
3 : 6 : 12 = 3/3: 6/3 : 12: 3
= 1 : 2 : 4
This proves the law of multiple proportions as we get the ratio of whole numbers for hydrogen from the its ratio of different compounds formed with carbon.
Explanation:
C respectively.
As per the given data, the percentage of hydrogen in A, B and C are 25%, 14.3% and 7.7% respectively.
In A, 1 part of hydrogen is combined with 3 parts of carbon.
In B, 1 part of hydrogen is combined with 6 parts of carbon.
In C, 1 part of hydrogen is combined with 12 parts of carbon.
Therefore, the weights of carbon combining with 1 part of hydrogen are in the ratio of 1 : 2 : 4.
Thus, this data illustrates the law of multiple proportions.