carbon and oxygen combine in the ratio of 3 is to 8 by mass to form seo2 what mass of Oxygen will be required to react completely with 9 gram of carbon
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Let the weight of carbon used to react be xx. Thus,
x32∴xx=38=38×32=12gx32=38∴x=38×32x=12g
Therefore the weight of carbon to be used for complete combustion of 32g of oxygen is 12g
x32∴xx=38=38×32=12gx32=38∴x=38×32x=12g
Therefore the weight of carbon to be used for complete combustion of 32g of oxygen is 12g
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