Question

carbon dioxide and another gas x has their rates of diffusion as 0.290 cc/s respectively .find the water vapour density of the gas x if the vapour density of carbon dioxide is 22​

Answer 1

Answer:

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Answer 2

Explanation:

rate of diffusion of co2/rate of diffusion of gas'x'

=√vd of gas'x'/vd of co2

0.290ccs/0.271ccs

=√vd of gas 'x'/22

=vd of gas'x'

=0.290×0.290×22/0.271×0.271

=25.19