Question

carbon is found to form two oxides which contain 42.9% and 27.3% carbon respectively.show that these  figures illustrate law of multiple proportion.

Answer 1

Answer:

Explanation:

% composition of carbon in different oxides – Element First oxide Second oxide carbon 42.9% 27.3% oxygen 100-42.9=57.1 100-27.3=72.7 In the first oxide, 57.1 part by mass of oxygen with 42.9 parts by mass of carbon Therefore-1 part oxygen will combine with carbon=42.9/57.1=0.751 Similarly In the second oxide contains oxygen72.7 parts with 27.3 parts carbon One part oxygen combines with carbon =27.3/72.7=0.376 The ratio of the masses of carbon that combine with the same mass oxygen is =0.751:0.376 Or 2:1, since this is a simple whole numbers ratio, so the above data illustrate the law of multiple proportions.

Thanku....

Answer 2

Answer:

Explanation:

% composition of carbon in different oxides – Element First oxide Second oxide carbon 42.9% 27.3% oxygen

100-42.9=57.1 100-27.3=72.7 In the first oxide

, 57.1 part by mass of oxygen with 42.9 parts by mass of carbon

Therefore-1 part oxygen will combine with carbon=42.9/57.1=0.751

Similarly In the second oxide contains oxygen72.7 parts with 27.3 parts

carbon One part oxygen combines with carbon =27.3/72.7=0.376.

The ratio of the masses of carbon that combine with the same mass oxygen is =0.751:0.376

Or

2:1, since this is a simple whole numbers ratio, so the above data illustrate the law of multiple proportions.