Carbon monoxide is more effective reducing agent than carbon below 983 K but above this temperature the
reverse is true. How would you explain this?
Answers
Answered by
25
The two reactions are as :
C(s) + O2 CO2 ......(i)
2C(s) + O2 2CO ......(ii)
2CO + O2 2CO2 ......(iii)
C+
O (iii)
(i)
(ii)
G°
T 983 K
2CO+O 2CO 2 2
2C +O
2CO (s) 2
Below 983 K reaction 2CO + O2 2CO2 is more favoured due to more negative G value thus CO is
better reducing agent than carbon.
Above 983 K, reaction 2C(s) + O2 2CO has more negative G than oxidation of CO to CO2, so carbon
will be better reducing agent
C(s) + O2 CO2 ......(i)
2C(s) + O2 2CO ......(ii)
2CO + O2 2CO2 ......(iii)
C+
O (iii)
(i)
(ii)
G°
T 983 K
2CO+O 2CO 2 2
2C +O
2CO (s) 2
Below 983 K reaction 2CO + O2 2CO2 is more favoured due to more negative G value thus CO is
better reducing agent than carbon.
Above 983 K, reaction 2C(s) + O2 2CO has more negative G than oxidation of CO to CO2, so carbon
will be better reducing agent
Answered by
6
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