Question

Carbon monoxide reacts with oxygen to form carbon dioxide by the following reaction, 2co+o2 = 2co2. in an experiment, 400ml of carbon monoxide and 180ml of oxygen were allowed to react, when 80% of carbon monoxide was transformed to carbon dioxide. All the volumes were measured under the same conditions of temperature and pressure. Find out the composition of the final mixture.

Answer 1

Answer:

Explanation:

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n(C)=m(C)M(C)=12 g/12 gmol^−1=1 mol

n(O2)=m(O2)M(O2)=20 g32 gmol^-1=0.625 mol

x+y0.5             total amount of carbon

x+y=1=0.625  total amount of oxygen

Solving this system of equations, we get x=0.75 (mol) and y=0.25 (mol). Hence the masses of the products are:

m(CO)m(CO2)=x⋅M(CO)= 0.75 mol x 28 gmol^−1

y⋅M(CO2)==0.25 mol x 44 gmol^−1=21 g=11 g

Answer 2

Answer:

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