carbon with percentage of 92.32 and the rest is hydrogen , which acts as welding fuel gas , calculate the empirical and molecular formula. The molar mass of the compound is 25.98
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empirical formula = (CH)ₙ
molecular formula = C₂H₂
Explanation:
molar mass = 25.98
let total mass be 100 gram
mass of C =92.32
mass of H = 7.68
relative no of moles of C = 92.32 / 12
= 7.69
relative no of moles of H = 7.68/ 1
= 7.68
simplest mole ratio = relative no of moles of C / relative no of moles of H
= 7.69 / 7.68
= 1
Empirical formula = (CH )ₙ
as molar mass = 25.98
molar mass of CH = 12+1 = 13
n = 25.98 /13
= 2
MOLECULAR FORMULA = (CH)₂
= C₂H₂
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