Question

Cards are natural numbers from 4 to 56. A card is drawn randomly find the prob-

ability of getting i) Factors of 60 ii) Multiple of 12 iii)Two digit number

whose sum is 7 iv) perfect square.​

Answer 1

Answer:

i)8/52

ii)4/52

iii)5/52

iv)3/52

Answer 2

Solution!!

The concept of probability has to be used here. Given that the cards are natural numbers from 4 to 56.

So, the cards are 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55 and 56.

Hence, total number of cards = 53

A card is drawn randomly. The probability that the card is :-

(i) factor of 60 is 9/53

Explanation:

Factors of 60 from 4 to 56 are 4, 5, 6, 10, 12, 15, 20, 30 and 60.

There are total 9 factors.

Number of favourable outcomes = 9

Probability = Number of favourable outcomes ÷ Total number of outcomes

Probability = 9/53

(ii) multiple of 12 is 4/53

Explanation:

Multiples of 12 from 4 to 56 are 12, 24, 36 and 48.

There are total 4 multiples.

Number of favourable outcomes = 4

Probability = Number of favourable outcomes ÷ Total number of outcomes

Probability = 4/53

(iii) two digit number whose sum is 7 is 5/53

Explanation:

Two digit numbers whose sum is 7 from 4 to 56 are 16, 25, 34, 43 and 52.

There are total 5 such numbers.

Number of favourable outcomes = 5

Probability = Number of favourable outcomes ÷ Total number of outcomes

Probability = 5/53

(iv) perfect square is 6/53

Explanation:

Perfect squares from 4 to 56 are 4, 9, 16, 25, 36 and 49.

There are total 6 perfect squares.

Number of favourable outcomes = 6

Probability = Number of favourable outcomes ÷ Total number of outcomes

Probability = 6/53