Cards bearing number 1,3,5,7.....35 are kept in a bag. a card is drawn at random from the bag find the probability of getting a card bearing. 1) a prime number less than 50. 2)a number divisible by 3 and 5. and miltiple of 7
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Firstly,
probability = no. of possible cases/ total no. of cases
1) possibilities for a prime number = 3, 5, 7, 11, 13, 17, 19, 23, 29, 31
prime numbers above 35 are not available because last card is 35.
No. of possibilities = 10
Total no. of cards = 18
Probability for a prime no. card = 10/18 = 5/9
2)
possibilities for a no. divisible by 3 and 5 = 15
probability for a no. divisible by 3 and 5 = 1/18
3) possibilities for a multiple of 7 = 7, 21, 35
no. of possibilities = 3
probability for a multiple of 7 = 3/18 = 1/6
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