Question

Cards bearing numbers 10, 11, 12…..…30 are kept in a bag . A card is drawn at random from
the bag. The probability of getting a card with a prime number is ….. (a) 2/7 (b) 1/3 (c) 3/10 (d) 7/20

Answer 1

Answer: (c) option/ 3/10

Step-by-step explanation:total no. Of prime nos. From 10 to 30

= 6

Total no. Of cards

=20

So 6/20

= 3/10

I hope it will help you

Answer 2

Answer:

P(prime) { 11, 13, 17, 19, 23, 29 }

P(e) = nP(prime)/total outcomes

= P(e) = 6/20

=> 3/10

option C