Math, asked by Anonymous, 1 year ago

Cards bearing numbers 3,5...35 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card bearing
(a)prime number less than 15
(b) a number divisible by 3 and 5

Answers

Answered by rphit
27
this is the right answer bro
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Anonymous: thnk u
Answered by RenatoMattice
14

Answer:  a) \frac{5}{17}

b) \frac{9}{17}

Step-by-step explanation:

Since we have given that

Number written on cards = 3,5............35

(a) prime number less than 15

Favourable outcomes is given by

\{3,5,7,11,13\}

Number of favourable outcomes = 5

Total number of outcomes = 17

So, Probability of getting a prime number less than 15 is given by

\frac{\text{Number of favourable outcome}}{\text{ Total number of outcomes}}\\\\=\frac{5}{17}

(b) a number divisible by 3 and 5

Favourable outcomes is given by

\{3,5,9,15,21,25,27,33,35\}

Number of favourable outcome = 9

So, Probability of getting a number divisible by 3 and 5 is given by

\frac{\text{Number of favourable outcome}}{\text{ Total number of outcomes}}\\\\=\frac{9}{17}

Hence, a) \frac{5}{17}

b) \frac{9}{17}

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